Introduction
Sequences and series convergence tests are essential tools in calculus that help determine whether infinite sums approach a finite value. Understanding these tests is crucial for analyzing functions, solving differential equations, and approximating complex expressions. This cheatsheet provides a comprehensive reference for the most important convergence tests and their applications.
Core Concepts of Sequences and Series
Sequences
- A sequence is an ordered list of numbers: {a₁, a₂, a₃, …} or {aₙ}
- A sequence converges if lim(n→∞) aₙ exists and equals a finite value
- A sequence diverges if the limit doesn’t exist or equals ±∞
Series
- A series is the sum of terms in a sequence: a₁ + a₂ + a₃ + … or Σaₙ
- Convergent series: The sum approaches a finite value as n→∞
- Divergent series: The sum grows without bound or oscillates
- Partial sum: Sₙ = a₁ + a₂ + … + aₙ
- A series converges if lim(n→∞) Sₙ exists and equals a finite value
Convergence Tests for Series
1. Divergence Test (nth Term Test)
- Statement: If lim(n→∞) aₙ ≠ 0, then Σaₙ diverges
- Contrapositive: If Σaₙ converges, then lim(n→∞) aₙ = 0
- Note: If lim(n→∞) aₙ = 0, the series may still diverge
- Example: Harmonic series Σ(1/n) diverges despite lim(n→∞) 1/n = 0
2. Geometric Series Test
- Form: Σarⁿ⁻¹ from n=1 to ∞
- Convergence: Converges if |r| < 1
- Sum: If |r| < 1, then Σarⁿ⁻¹ = a/(1-r)
- Example: Σ(1/2)ⁿ converges to 1/(1-1/2) = 2
3. p-Series Test
- Form: Σ(1/nᵖ) from n=1 to ∞
- Convergence:
- Converges if p > 1
- Diverges if p ≤ 1
- Examples:
- Σ(1/n²) converges (p = 2 > 1)
- Σ(1/n) diverges (p = 1 ≤ 1)
4. Comparison Test
- Statement: If 0 ≤ aₙ ≤ bₙ for all n ≥ N:
- If Σbₙ converges, then Σaₙ converges
- If Σaₙ diverges, then Σbₙ diverges
- Best used: When series terms can be bounded by a known series
5. Limit Comparison Test
- Statement: If aₙ, bₙ > 0 and lim(n→∞) aₙ/bₙ = c where c > 0:
- Σaₙ and Σbₙ either both converge or both diverge
- Best used: When two series behave similarly as n→∞
- Example: Compare Σ(n/(n²+1)) with Σ(1/n)
6. Ratio Test
- Statement: Let L = lim(n→∞) |aₙ₊₁/aₙ|
- If L < 1: Series converges absolutely
- If L > 1: Series diverges
- If L = 1: Test is inconclusive
- Best used: For series with factorials or exponentials
- Example: Σ(2ⁿ/n!) converges as L = lim(n→∞) 2/(n+1) = 0 < 1
7. Root Test
- Statement: Let L = lim(n→∞) ⁿ√|aₙ|
- If L < 1: Series converges absolutely
- If L > 1: Series diverges
- If L = 1: Test is inconclusive
- Best used: When aₙ involves powers like nⁿ
- Example: Σ(1/nⁿ) converges as L = lim(n→∞) (1/n) = 0 < 1
8. Integral Test
- Statement: If f(x) is positive, continuous, and decreasing for x ≥ N, and aₙ = f(n), then:
- Σaₙ converges if and only if ∫ₙ^∞ f(x)dx converges
- Best used: When aₙ can be represented as a continuous function
- Example: For Σ(1/n²), use f(x) = 1/x² and ∫₁^∞ (1/x²)dx = 1
9. Alternating Series Test (Leibniz Test)
- Form: Σ(-1)ⁿ⁻¹bₙ or Σ(-1)ⁿbₙ where bₙ > 0
- Convergence: Converges if:
- bₙ₊₁ ≤ bₙ for all n ≥ N (decreasing sequence)
- lim(n→∞) bₙ = 0
- Error bound: |Sₙ – S| ≤ bₙ₊₁
- Example: Σ(-1)ⁿ⁻¹(1/n) converges (alternating harmonic series)
10. Absolute Convergence Test
- Statement: If Σ|aₙ| converges, then Σaₙ converges
- Note: A series can converge conditionally (Σaₙ converges but Σ|aₙ| diverges)
- Best used: After using ratio or root test on |aₙ|
- Example: Σ(-1)ⁿ⁻¹(1/n) converges conditionally because Σ(1/n) diverges
11. Direct Comparison Test
- Statement: If 0 ≤ aₙ ≤ bₙ for all n ≥ N:
- If Σbₙ converges, then Σaₙ converges
- If Σaₙ diverges, then Σbₙ diverges
- Example: Compare Σ(1/(n²+n)) with Σ(1/n²)
12. Cauchy Condensation Test
- Statement: For a non-increasing sequence aₙ > 0, Σaₙ converges if and only if Σ2ᵏa₂ᵏ converges
- Best used: For series where comparison is difficult
- Example: For Σ(1/n), check Σ2ᵏ(1/2ᵏ) = Σ1, which diverges
Comparison Table of Convergence Tests
Test Name | When to Use | Limitations | Example Series |
---|---|---|---|
Divergence Test | First check for any series | Only proves divergence | Σ(n/(n+1)) |
Geometric Series | When aₙ = arⁿ⁻¹ | Only for geometric series | Σ(3·2⁻ⁿ) |
p-Series | When aₙ = 1/nᵖ | Only for p-series | Σ(1/n³) |
Comparison | When terms comparable to known series | Requires finding suitable series to compare | Σ(1/(n²+3)) |
Limit Comparison | When ratio of terms approaches non-zero limit | Requires finding suitable series to compare | Σ(n²/(n³+1)) |
Ratio Test | When terms involve factorials/powers | Inconclusive if limit equals 1 | Σ(nⁿ/n!) |
Root Test | When terms involve nth powers | Inconclusive if limit equals a 1 | Σ((0.9)ⁿ) |
Integral Test | When series matches integrable function | Requires calculus of integrals | Σ(1/(n·ln²(n))) |
Alternating Series | For alternating sign series | Only for alternating series | Σ((-1)ⁿ⁻¹/n²) |
Absolute Convergence | After trying ratio/root test | May need to check conditional convergence | Σ((-1)ⁿ/n²) |
Common Challenges and Solutions
Challenge 1: Choosing the Right Test
- Solution: Follow a systematic approach:
- Check if lim(n→∞) aₙ = 0 (if not, series diverges)
- Identify series type (geometric, alternating, etc.)
- For positive series, try comparison, ratio, or integral tests
- For alternating series, check the alternating series test first
Challenge 2: Dealing with Complex Terms
- Solution:
- Break into simpler components
- Use algebraic manipulations
- Apply limits to simplify expressions
- Example: For Σ(n²+1)/(n³+n), simplify to Σ(1/n + 1/n³) as n→∞
Challenge 3: Inconclusive Tests
- Solution:
- If ratio/root test gives L = 1, try another test
- Combine multiple tests when necessary
- Example: For Σ(1/n·ln(n)), ratio test is inconclusive, but integral test works
Challenge 4: Determining Absolute vs. Conditional Convergence
- Solution:
- First check if Σ|aₙ| converges (absolute convergence)
- If Σ|aₙ| diverges but series contains alternating signs, check for conditional convergence
- Example: Σ(-1)ⁿ⁻¹/n is conditionally convergent
Best Practices and Tips
Tip 1: Simplification Strategy
- Always simplify terms before applying tests
- Use asymptotic behavior (what happens as n→∞)
- Focus on highest-order terms for large n
- Example: Σ(n²+n)/(n³+5) ≈ Σ(n²/n³) = Σ(1/n) as n→∞
Tip 2: Test Selection Guide
- For series with factorials: Ratio Test
- For series with nth powers: Root Test
- For alternating series: Alternating Series Test
- For positive series comparable to known series: Comparison Tests
- For series expressible as a function: Integral Test
Tip 3: Common Convergent Series
- Σ(1/n²) converges to π²/6
- Σ(1/n(n+1)) converges to 1
- Σ(r^n) converges to 1/(1-r) for |r| < 1
- Σ((-1)ⁿ⁻¹/n) converges to ln(2)
Tip 4: Common Divergent Series
- Σ(1/n) (harmonic series)
- Σ(1/n^p) for p ≤ 1
- Σ(n/(n+1))
- Σ(1/ln(n))
Resources for Further Learning
Textbooks
- Calculus by James Stewart
- Thomas’ Calculus by George B. Thomas
- Advanced Calculus by Lynn H. Loomis and Shlomo Sternberg
Online Resources
- Khan Academy: Sequences and Series
- MIT OpenCourseWare: Single Variable Calculus
- Paul’s Online Math Notes: Calculus II
- 3Blue1Brown YouTube channel for visual intuition
Practice Resources
- Brilliant.org (interactive calculus problems)
- Wolfram Alpha (verify solutions)
- PatrickJMT YouTube videos for worked examples
Quick Reference: Series Convergence Flowchart
Apply Divergence Test
- If lim(n→∞) aₙ ≠ 0 → DIVERGES
- If lim(n→∞) aₙ = 0 → CONTINUE TESTING
Check series type:
- If geometric series (ar^(n-1)) → CONVERGES if |r| < 1
- If p-series (1/n^p) → CONVERGES if p > 1
- If alternating → Try Alternating Series Test
For positive series:
- Try Ratio Test
- Try Root Test
- Try Comparison Tests
- Try Integral Test
If alternating:
- Check absolute convergence first
- If absolutely convergent → CONVERGES
- If not, check Alternating Series Test conditions